Abstract
The singular boundary-value problem (g(x′))′ = μf(t,x,x′), x′(0) = 0, x(T) = b > 0 is considered. Here μ is the parameter and f(t,x,y), which satisfies local Carathéodory conditions on [0, T] × (ℝ\{b}) × (ℝ\{0}), may be singular at the values x = b and y = 0 of the phase variables x and y, respectively. Conditions guaranteeing the existence of a positive solution to the above problem for suitable positive values of μ are given. The proofs are based on regularization and sequential techniques and use the topological transversality theorem.
| Original language | English |
|---|---|
| Pages (from-to) | 1-13 |
| Number of pages | 13 |
| Journal | Proceedings of the Edinburgh Mathematical Society |
| Volume | 47 |
| Issue number | 1 |
| DOIs | |
| Publication status | Published - 1 Feb 2004 |
Keywords
- Mixed condition
- Positive solution
- Singular boundary-value problem
- Topological transversality theorem
Authors (Note for portal: view the doc link for the full list of authors)
- Authors
- Agarwal, RP;O'Regan, D;Stanek, S